A) 50 mol per cent
B) 54 mol per cent
C) 32 mol per cent
D) 44 mol per cent
Correct Answer: A
Solution :
Let the amount of A in the mixture be \[{{\chi }_{A}}\] and be \[{{\chi }_{B}}\]. \[{{p}_{T}}=760={{p}^{o}}_{A}{{\chi }_{A}}+{{p}^{o}}{{\chi }_{B}}\] \[760=520{{\chi }_{A}}+1000\,\,(1-{{\chi }_{A}})\] \[480{{\chi }_{A}}=240\] \[{{\chi }_{A}}=\frac{1}{2}\] or 50 mol percentYou need to login to perform this action.
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