A) 8.53
B) 7.51
C) 8.92
D) 9.86
Correct Answer: D
Solution :
\[{{E}_{2}}=\frac{-1.312\times {{10}^{6}}\times {{(1)}^{2}}}{{{(2)}^{2}}}\] \[=-3.28\times {{10}^{-5}}J/mol\] \[{{E}_{1}}=-1.312\times {{10}^{6}}J/mol\] \[\therefore \] \[\Delta E={{E}_{2}}-{{E}_{1}}\] \[=-3.28\times {{10}^{5}}-(-1.312\times {{10}^{6}})\] \[=9.84\times {{10}^{5}}J/mol\]You need to login to perform this action.
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