BCECE Medical BCECE Medical Solved Papers-2015

  • question_answer
    Consider the following reaction, \[ZnC{{l}_{2}}+NaOH\xrightarrow{{}}\underset{White\text{ }ppt.}{\mathop{B}}\,\xrightarrow{NaOH}\underset{Soluble}{\mathop{C}}\,\] Then, the final product C is

    A)  \[N{{a}_{2}}Zn{{O}_{2}}\]   

    B)  \[Zn{{(OH)}_{2}}\]

    C)  ZnO             

    D)  \[ZnS{{O}_{4}}\]

    Correct Answer: A

    Solution :

    Salts like \[ZnC{{l}_{2}},SnC{{l}_{2}},\,AlC{{l}_{3}}\], etc, give white precipitate with \[NaOH\], however precipitate dissolves in excess of it. \[ZnC{{l}_{2}}+2NaOH\xrightarrow{{}}\underset{\begin{smallmatrix}  (White\text{ }ppt.) \\  B \end{smallmatrix}}{\mathop{Zn{{(OH)}_{2}}}}\,\xrightarrow{NaOH}\underset{\begin{smallmatrix}  Soluble \\  C \end{smallmatrix}}{\mathop{N{{a}_{2}}Zn{{O}_{2}}}}\,\]


You need to login to perform this action.
You will be redirected in 3 sec spinner