A) 7.2g
B) 2:3 g
C) 1.8g
D) 4.1 g
Correct Answer: C
Solution :
1 mole of NO gives = 1 mol \[N{{O}_{2}}\] Hence, \[1.20\,\,g\,NO=\frac{1.20}{30}\,mol\] gives \[=1\times \frac{1.20}{30}mol\,N{{O}_{2}}=\frac{1.20}{30}\times 46\,g\,N{{O}_{2}}=1.84\,g\,N{{O}_{2}}\]You need to login to perform this action.
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