A) NaCI
B) \[N{{a}_{2}}S{{O}_{4}}\]
C) \[N{{a}_{3}}P{{O}_{4}}\]
D) \[A{{s}_{2}}{{S}_{3}}\]
Correct Answer: C
Solution :
\[Fe{{(OH)}_{3}}\] is a positively charged sol. According to Hardy Schulze rule, greater the charge on an oppsitely charged ion of the electrolyte added, more effective it is in bringing about the coagulation. Hence, \[N{{a}_{3}}P{{O}_{4}}\] (containing \[PO_{4}^{3-}\] ions) is most effective.
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