A) acetic acid
B) iodo acetic acid
C) formic acid
D) None of these
Correct Answer: A
Solution :
\[\underset{Glycolic\text{ }acid}{\mathop{HOOC-C{{H}_{2}}OH}}\,\xrightarrow{HI}\underset{Acetic\text{ }acid}{\mathop{HOOC-C{{H}_{3}}}}\,\] HI reduces \[C{{H}_{2}}OH\] to \[C{{H}_{3}}\] but \[HI+P\] reduces both \[COOH\] and \[C{{H}_{2}}OH\] to \[C{{H}_{3}}9\].
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