A) \[{{K}^{2}}\]
B) \[\sqrt{K}\]
C) \[\frac{1}{\sqrt{K}}\]
D) \[\frac{1}{{{K}^{2}}}\]
Correct Answer: A
Solution :
\[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\] \[K=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\] ...(i) \[2{{N}_{2}}+6{{H}_{2}}4N{{H}_{3}}\] \[K'=\frac{{{[N{{H}_{3}}]}^{4}}}{{{[{{N}_{2}}]}^{2}}{{[{{H}_{2}}]}^{6}}}\] ?. (ii) From Eqs. (i) and (ii) \[K'={{K}^{2}}\]
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