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  3. BHU PMT

BHU PMT BHU PMT (Mains) Solved Paper-2006

  • question_answer
    A rigid container with thermally insulated walls contains a coil of resistance\[100\,\,\Omega ,\] carrying current 1A. Change in internal energy after 5 min will be:

    A)  zero                                     

    B)  10 kJ

    C)  20 kJ                                    

    D)  30 kJ

    Correct Answer: D

    Solution :

                     \[W=0\]Therefore,  from  first  law  of thermodynamics \[\Delta U=\Delta Q={{i}^{2}}Rt\] \[={{(1)}^{2}}\times 100(5\times 60)\] \[=30kJ\]


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