A) 500s
B) 20s
C) 35ms
D) 1ms
Correct Answer: D
Solution :
The current time (i-c) equation in L-R circuit is given by (growth of current in L-R circuit) \[i={{i}_{0}}(1-{{e}^{-t/{{\tau }_{L}}}})\] ...(1) where \[{{i}_{0}}=\frac{V}{R}=\frac{12}{6}=2A\] and \[{{\tau }_{L}}=\frac{L}{R}=\frac{8.4\times {{10}^{-3}}}{6}=1.4\times {{10}^{-3}}s\] and \[i=1A\] (given) Substituting these values in Eq. (1) we get \[t=0.97\times {{10}^{-3}}s\] Or \[t\approx 1\,ms\]You need to login to perform this action.
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