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BHU PMT BHU PMT (Mains) Solved Paper-2006

  • question_answer
    The radius of gyration of a slender rod of mass M and length L about an axis of rotation perpendicular to its length and passing through the centre is:

    A)  \[\frac{L}{\sqrt{3}}\]                                     

    B)  \[\frac{L}{2}\]

    C)   \[\frac{L}{2\sqrt{3}}\]                 

    D)  \[\frac{2L}{\sqrt{3}}\]

    Correct Answer: D

    Solution :

                     Here, \[I=\frac{M{{L}^{2}}}{12}\]and as \[I=M{{K}^{2}}\] \[\therefore \]  \[M{{K}^{2}}=\frac{M{{L}^{2}}}{12}\]i.e.,\[K=\frac{L}{2\sqrt{3}}\]


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