A) \[C{{u}^{2+}}\]
B) \[A{{g}^{+}}\]
C) \[Z{{n}^{2+}}\]
D) \[A{{u}^{+}}\]
Correct Answer: A
Solution :
Paramagnetic species has unpaired electron. \[C{{u}^{2+}}(Z=29):[Ar]3{{d}^{9}},4{{s}^{0}}\] \[C{{u}^{2+}}\]has one unpaired electron hence, it is paramagnetic in nature.
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