A) \[[Ag{{(N{{H}_{4}})}_{2}}]OH\]
B) \[[Ag{{(N{{H}_{3}})}_{2}}]OH\]
C) \[[Ag{{(N{{H}_{4}})}_{2}}]Cl\]
D) \[[Ag{{(N{{H}_{3}})}_{2}}]Cl\]
Correct Answer: D
Solution :
\[AgCl\]dissolves in\[N{{H}_{4}}OH\]due to the formation of\[[Ag{{(N{{H}_{3}})}_{2}}]Cl\] \[AgCl+2N{{H}_{4}}OH\xrightarrow{{}}\underset{dia\min eSilaver\,(I)\,}{\mathop{[Ag{{(N{{H}_{3}}]}_{2}}Cl}}\,+\underset{chloride}{\mathop{2{{H}_{2}}O}}\,\]
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