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BHU PMT BHU PMT (Mains) Solved Paper-2006

  • question_answer
    A compound of vanadium has a magnetic moment of 1.73 BM. What is the oxidation number of vanadium in the compound?

    A)  +4                                         

    B)  +3

    C)  +2                                         

    D)  +1

    Correct Answer: A

    Solution :

                     Magnetic moment \[(\mu )=\sqrt{n(n+2)}\] \[1.73=\sqrt{n(n+2)}\] \[3=n(n+2)\] \[n=1\] Hence, one unpaired electron in the vanadium ion. \[V(Z=23):[Ar]3{{d}^{3}}4{{s}^{2}}\]                 \[{{V}^{4+}}(Z=23):[Ar]3{{d}^{1}},4{{s}^{0}}\] Hence, oxidation state of vanadium is +4.


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