A) \[[Ag{{(N{{H}_{4}})}_{2}}]OH\]
B) \[[Ag{{(N{{H}_{3}})}_{2}}]OH\]
C) \[[Ag{{(N{{H}_{4}})}_{2}}]Cl\]
D) \[[Ag{{(N{{H}_{3}})}_{2}}]Cl\]
Correct Answer: A
Solution :
\[[Fe(CN)_{6}^{4-}]\]is diamagnetic due to the absence of unpaired electrons. It has\[{{d}^{2}}s{{p}^{3}}\] hybridisation.
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