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BHU PMT BHU PMT (Mains) Solved Paper-2006

  • question_answer
    The molal freezing point constant for water is \[1.86{}^\circ C\]per mol therefore, the freezing point of\[0.1M\text{ }NaCl\] solution in water is expected to be:

    A)  \[-1.86{}^\circ C\]                          

    B)  \[-0.186{}^\circ C\]

    C)  \[+0.372{}^\circ C\]                       

    D)  \[-0.372{}^\circ C\]

    Correct Answer: D

    Solution :

                     \[\Delta {{T}_{f}}=i\times {{k}_{f}}\times M\] \[=2\times 1.86\times 0.1\] \[=0.372\] \[\therefore \]freezing point\[=0-0.372\] \[=-0.372{}^\circ C\]


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