A) \[\frac{M}{3}\]
B) \[\frac{M}{5}\]
C) \[\frac{M}{2}\]
D) \[M\]
Correct Answer: D
Solution :
In alkaline medium \[\overset{+7}{\mathop{2KMn{{O}_{4}}}}\,+2KOH\xrightarrow{{}}\overset{+6}{\mathop{2{{K}_{2}}Mn{{O}_{4}}}}\,+{{H}_{2}}O+O\] Change in oxidation number\[=7-6=1\] Equivalent weight \[=\frac{molecular\text{ }weight}{change\text{ }in\text{ }oxidation\text{ }number}=\frac{M}{1}=M\]You need to login to perform this action.
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