A) \[-1.86{}^\circ C\]
B) \[-0.186{}^\circ C\]
C) \[+0.372{}^\circ C\]
D) \[-0.372{}^\circ C\]
Correct Answer: D
Solution :
\[\Delta {{T}_{f}}=i\times {{k}_{f}}\times M\] \[=2\times 1.86\times 0.1\] \[=0.372\] \[\therefore \]freezing point\[=0-0.372\] \[=-0.372{}^\circ C\]You need to login to perform this action.
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