A) 2
B) 4
C) 1
D) 3
Correct Answer: A
Solution :
Gram equivalent of acid = gram equivalent of \[KOH\] \[\frac{0.45}{E}=\frac{20\times 0.5}{1000}\] \[E=45\] \[Equivalent\text{ }weight=\frac{molecular\text{ }weight}{basicity}\] \[Basicity=\frac{90}{45}=2\]You need to login to perform this action.
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