Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
The Cannizaro reaction is given by: (1)\[HCHO\] (2) \[{{C}_{6}}{{H}_{5}}CHO\] (3) \[{{(C{{H}_{3}})}_{3}}CCHO\] (4)\[C{{H}_{3}}CHO\]A) 1, 2 and 3 are correct
B) 1 and 2 are correct
C) 2 and 4 are correct
D) 1 and 3 are correct
Correct Answer: A
Solution :
Aldehyde containing no a-hydrogen atom on reaction with 50%\[NaOH\]or KOH undergo disproportionation to give an alcohol and Na or K salt of an acid. This is called Cannizaro reaction. \[2HCHO+KOH\xrightarrow{\Delta }C{{H}_{3}}OH+HCOOK\] \[2C{{H}_{3}}\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-CHO\xrightarrow{\Delta }C{{H}_{3}}\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}OH+C{{H}_{3}}\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-COOK\]You need to login to perform this action.
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