BHU PMT BHU PMT (Mains) Solved Paper-2007

  • question_answer

    Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:

    In the circuit shown below, the cell is ideal, with emf = 2V. The resistance of the coil of the galvanometer G is\[1\,\Omega \]. Then (1) 0.2 A current flows in G (2) potential difference across\[{{C}_{1}}\]is 1 V (3) potential difference across\[{{C}_{2}}\]is 1.2 V (4) no current flows in G

    A)  1, 2 and 3 are correct

    B)  1 and 2 are correct

    C)  2 and 4 are correct

    D)  1 and 3 are correct

    Correct Answer: A

    Solution :

                     Disregard the capacitors and find the current through G. The potential difference across each capacitor is then found from the potential difference across the resistances in parallel with them.


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