Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
In pure rolling fraction of its total energy associated with rotation is\[\alpha \]for a ring and P for a solid sphere. Then (1) \[\alpha =1/2\] (2) \[\beta =2/7\] (3) \[\beta =2/5\] (4)\[\alpha =1/4\]A) 1, 2 and 3 are correct
B) 1 and 2 are correct
C) 2 and 4 are correct
D) 1 and 3 are correct
Correct Answer: B
Solution :
In case of pure rolling\[\frac{{{K}_{R}}}{{{K}_{T}}}=1\]for a ring and 2/5 for a solid sphere. Here\[{{K}_{R}}=\]rotational kinetic energy and\[{{K}_{T}}=\] translational kinetic energy. Therefore, fraction of its total energy associated with rotation is \[\alpha =\frac{1}{1+1}=\frac{1}{2}\] for ring and \[\beta =\frac{2}{2+5}=\frac{2}{7}\]for solid sphere.
You need to login to perform this action.
You will be redirected in
3 sec
