A) \[7.22{}^\circ C\]
B) \[8.94{}^\circ C\]
C) zero
D) \[5{}^\circ C\]
Correct Answer: A
Solution :
The heat required at constant pressure \[Q=n{{C}_{p}}\Delta T\] \[\therefore \]Change in temperature \[\Delta T=\frac{Q}{n{{C}_{p}}}\] Here : \[Q=300\text{ }J,\text{ }n=2mole\] \[{{C}_{p}}=\frac{5}{2}R\] R, the gas constant \[=8.31\text{ }J\text{ }mo{{l}^{-1}}{{\text{K}}^{-1}}\] \[\therefore \] \[\Delta T=\frac{300}{2\times \frac{5}{2}\times 8.31}\] \[=\frac{300}{5\times 8.31}={{7.22}^{o}}C\]
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