A) 24 min
B) 16 min
C) 8 min
D) 48 min
Correct Answer: B
Solution :
First order reaction, \[k=\frac{2.303}{t}\log \frac{a}{a-x}\] Here, \[\therefore \] \[a=100\] \[\therefore \] \[x=75%\] \[\because \] \[a-x=(100-75)%=25%\] \[k=\frac{2.303}{32}\log \frac{100}{25}\] \[=\frac{2.303}{32}\log 4\] \[=\frac{2.303\times \log {{2}^{2}}}{32}\] \[=\frac{2.303\times 2\log 2}{32}\] \[=\frac{2.303\times 2\times 0.3010}{32}=\frac{2\times 0.63}{32}\] \[\therefore \] \[{{t}_{1/2}}=\frac{0.693}{k}\]\[\therefore \]\[{{t}_{1/2}}=\frac{0.693}{2\times 0.693/32}\] \[=16\text{ }min\]
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