A) 4.0
B) 8.0
C) 32.0
D) 64.0
Correct Answer: D
Solution :
\[\frac{Rate\text{ }of\text{ }diffusion\text{ }of\text{ }methane({{r}_{C{{H}_{4}}}})}{Rate\text{ }of\text{ }diffusion\text{ }of\text{ }gas\,'X'({{r}_{X}})}\] \[=\sqrt{\frac{mol.\text{ }wt.\text{ }of\text{ }gas({{M}_{X}})}{mol.\text{ }wt.\text{ }of\text{ }methane({{M}_{C{{H}_{4}}}})}}\] \[\frac{{{r}_{C{{H}_{4}}}}}{{{r}_{X}}}=2\sqrt{\frac{{{M}_{X}}}{{{M}_{C{{H}_{4}}}}}}\] \[=2\sqrt{\frac{{{M}_{X}}}{16}}\] \[{{M}_{X}}=16\times {{(2)}^{2}}=64\]
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