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BHU PMT BHU PMT (Mains) Solved Paper-2007

  • question_answer
    The amount of heat released when 20 mL of \[0.5\text{ }M\text{ }NaOH\]is mixed with 100 mL of 0.1 M \[HCl\]is\[x\text{ }kJ\]. The heat of neutralisation (in kJ \[mo{{l}^{-1}}\]) is

    A)  \[-100\text{ }x\]                             

    B)  \[-50\text{ }x\]

    C)   \[+100\text{ }x\]                           

    D)  \[+50\text{ }x\]

    Correct Answer: A

    Solution :

                                    Equivalents of\[NaOH=\frac{20\times 0.5}{1000}=0.01\] Equivalents of \[HCl=\frac{100\times 0.1}{1000}=0.01\] \[0.01\]equivalents, of acid and base release heat\[=-x\,kJ\] \[\therefore \]1 equivalents of acid and base release heat                 \[=\frac{-x}{0.0.1}\times 1=-100x\,kJ\]


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