A) \[{{I}_{2}}{{O}_{4}}\]
B) \[{{I}_{2}}{{O}_{5}}\]
C) \[{{I}_{2}}{{O}_{7}}\]
D) \[{{I}_{2}}{{O}_{9}}\]
Correct Answer: B
Solution :
In, general, higher the oxidation state, more is the covalent character of the oxide,\[{{I}_{2}}{{O}_{7}}\]and\[{{I}_{2}}{{O}_{9}}\]do not exist.\[{{I}_{2}}{{O}_{4}}\]is ionic in nature. It is intact iodyl iodate\[{{[IO]}^{+}}{{[I{{O}_{3}}]}^{-}}\]. The only covalent oxide of iodine is \[{{I}_{2}}{{O}_{5}}.\]
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