BHU PMT BHU PMT (Mains) Solved Paper-2008

  • question_answer
    The velocities of light in two different mediums are\[2\times {{10}^{8}}m{{s}^{-1}}\]and\[2.5\times {{10}^{8}}m{{s}^{-1}}\]respectively. The critical angle for these mediums is

    A)  \[{{\sin }^{-1}}\left( \frac{1}{5} \right)\]                               

    B)  \[{{\sin }^{-1}}\left( \frac{4}{5} \right)\]

    C)   \[{{\sin }^{-1}}\left( \frac{1}{2} \right)\]                              

    D)  \[{{\sin }^{-1}}\left( \frac{1}{4} \right)\]

    Correct Answer: B

    Solution :

                     Critical angle is given by \[\sin C=\mu -\frac{{{v}_{1}}}{{{v}_{2}}}\]                            \[=\frac{2\times {{10}^{8}}}{2.5\times {{10}^{8}}}=2.14\,m\] Or           \[C={{\sin }^{-1}}\left( \frac{4}{5} \right)\]


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