question_answer

The equivalent capacity between the points\[X\]and Y in the circuit with\[C=1\text{ }\mu F\]is

A)  \[2\mu F\]                        

B)  \[3\mu F\]

C)  \[1\mu F\]                                        

D)  \[0.5\mu F\]

Correct Answer: A

Solution :

                 The circuit is shown in the figure. As points a and b are at same potential, so no charge flows through ab. Now two remaining capacitors are in parallel, hence                 \[{{C}_{eq}}=C+C=2C\]                       \[=2\times 1=2\mu F\]