A) 30 N
B) 26 N
C) 20 N
D) 6N
Correct Answer: C
Solution :
Tension in the string when it makes angle\[\theta \]with the vertical, \[T=\frac{m{{v}^{2}}}{r}+mg\,\cos \theta \] When the string is horizontal,\[\theta =90{}^\circ \] Here,\[m=0.6\text{ }kg,\text{ }r=0.75\text{ }m,\text{ }v=5\text{ }m/s\] Hence, \[T=\frac{m{{v}^{2}}}{r}+mg\times 0=\frac{m{{v}^{2}}}{r}\] \[\therefore \] \[T=\frac{0.6\times {{(5)}^{2}}}{0.75}=20\,N\]You need to login to perform this action.
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