A) 2 : 3
B) 2 : 5
C) 3 : 2
D) 5 : 2
Correct Answer: C
Solution :
Thermal stress\[=Y\times strain\] or \[S=Y\varepsilon \] or \[S=Y\alpha t\] where\[\alpha =\]linear thermal expansion \[Y=\]Young's modulus Here, \[{{S}_{1}}={{S}_{2}}\] \[\Rightarrow \] \[{{Y}_{1}}{{\alpha }_{1}}t={{Y}_{2}}{{\alpha }_{2}}t\] Or \[\frac{{{Y}_{1}}}{{{Y}_{1}}}=\frac{{{\alpha }_{2}}}{{{\alpha }_{1}}}=\frac{3}{2}\] Thus, \[{{Y}_{1}}:{{Y}_{2}}=3:2\]You need to login to perform this action.
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