A) \[X(\alpha ,\text{ }p)Y\]
B) \[X(\alpha ,\text{ n})Y\]
C) \[X(p,\text{ n})Y\]
D) \[X(d,\text{ p})Y\]
Correct Answer: D
Solution :
Isotopes are the species having same atomic number and different atomic mass. \[_{a}{{X}^{b}}+\underset{\alpha -article}{\mathop{_{2}H{{e}^{4}}}}\,\to \underset{proton}{\mathop{_{1}{{H}^{1}}}}\,{{+}_{a+1}}{{Y}^{b+3}}(\alpha ,p\,type)\] \[_{a}{{X}^{b}}+\underset{\alpha -article}{\mathop{_{2}H{{e}^{4}}}}\,\to \underset{neutron}{\mathop{_{0}{{n}^{1}}}}\,{{+}_{a+2}}{{Y}^{b+3}}(\alpha ,n\,type)\] \[_{a}{{X}^{b}}+\underset{proton}{\mathop{_{1}{{H}^{1}}}}\,\to \underset{neutron}{\mathop{_{0}{{n}^{1}}}}\,{{+}_{a+1}}{{Y}^{b}}(p,n\,type)\] \[_{a}{{X}^{b}}+\underset{deutron}{\mathop{_{1}{{H}^{1}}}}\,\to \underset{proton}{\mathop{_{1}{{H}^{1}}}}\,{{+}_{a}}{{Y}^{b+1}}(d,p\,\,type)\] Only in option \[X\]and Y have same atomic number and different atomic mass, hence\[X\] and Y are isotopes in nuclear reaction given in option .You need to login to perform this action.
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