BHU PMT BHU PMT (Mains) Solved Paper-2008

  • question_answer
    The value of Planck's constant is\[6.63\times {{10}^{-34}}\] Js. The velocity of light is\[3.0\times {{10}^{8}}m{{s}^{-1}}\]. Which value is closest to the wavelength (in nm) of a quantum of light with frequency of\[8\times {{10}^{-1}}{{s}^{-1}}\]?

    A) \[4\times {{10}^{1}}\]                                   

    B) \[3\times {{10}^{7}}\]

    C) \[2\times {{10}^{-25}}\]                               

    D) \[5\times {{10}^{-18}}\]  

    Correct Answer: A

    Solution :

                     \[\Rightarrow \] \[Frequency=\frac{velocity\text{ }of\text{ }light\text{ }(c)}{wavelength\,(\lambda )}\] Given, frequency\[=8\times {{10}^{15}}{{s}^{-1}}\] velocity of light\[=3.0\times {{10}^{8}}m{{s}^{-1}}\] \[\therefore \]  \[8\times {{10}^{15}}=\frac{3\times {{10}^{8}}}{\lambda }\] or            \[\lambda =\frac{3\times {{10}^{8}}}{8\times {{10}^{15}}}=0.375\times {{10}^{-7}}m\]                 \[=3.75\times {{10}^{1}}nm\]                 \[\approx 40\,nm\]


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