A) Exothermic and decreasing disorder
B) Endothermic and increasing disorder
C) Exothermic and increasing disorder
D) Endothermic and decreasing disorder
Correct Answer: C
Solution :
We know that \[\Delta G=\Delta H-T\Delta S\] For exothermic reaction,\[\Delta H=-\text{ }ve\] For endothermic reaction,\[\Delta H=+\text{ }ve\] As disorder increases, \[\Delta S=+\text{ }ve\] As disorder decreases,\[\Delta S=-\text{ }ve\] For a spontaneous reaction\[\Delta G\]must be negative and for negative value of\[\Delta G,\text{ }\Delta H\] must be negative (ie, exothermic reaction) and\[\Delta S\]must be positive (ie, disorder increases) (according to the above equation).
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