A) \[1.0\times {{10}^{1}}\]
B) \[1.0\times {{10}^{5}}\]
C) \[1.0\times g{{10}^{10}}\]
D) \[1.0\times {{10}^{30}}\]
Correct Answer: C
Solution :
\[E_{cell}^{o}=\frac{0.0591}{n}\log K\] Given, \[n=1\] \[E_{cell}^{o}=0.591V\] \[0.591=\frac{0.0591}{1}\log K\] \[\log K=10\] \[K=1\times {{10}^{10}}\]
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