Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
The reagents,\[N{{H}_{4}}Cl\]and aqueous\[N{{H}_{3}}\]will precipitate (1) \[F{{e}^{3+}}\] (2) \[A{{l}^{3+}}\] (3) \[M{{g}^{2+}}\] (4)\[Z{{n}^{2+}}\]A) 1, 2 and 3 are correct.
B) 1 and 2 are correct.
C) 2 and 4 are correct.
D) 1 and 3 are correct.
Correct Answer: B
Solution :
\[N{{H}_{4}}Cl\]and aq\[N{{H}_{3}}\]are the group reagents for IIIrd group of qualitative inorganic analysis. Hence, they precipitate the radicals belongs to IIIrd group ie,\[F{{e}^{3+}},A{{l}^{3+}},C{{r}^{3+}}\] \[F{{e}^{3+}}+N{{H}_{4}}OH\xrightarrow{{}}\underset{brown\text{ }ppt.}{\mathop{Fe{{(OH)}_{3}}\downarrow }}\,+NH_{4}^{+}\] \[A{{l}^{3+}}+N{{H}_{4}}OH\xrightarrow{{}}\underset{whit\text{ }ppt.}{\mathop{Al{{(OH)}_{3}}\downarrow }}\,+NH_{4}^{+}\]
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