Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
Which of the following can show coordination isomerism? (1) \[[Cu{{(N{{H}_{3}})}_{4}}][PtC{{l}_{4}}]\] (2) \[{{[Fe{{(N{{H}_{3}})}_{6}}]}_{2}}{{[Pt{{(CN)}_{6}}]}_{3}}\] (3) \[[Co{{(N{{H}_{3}})}_{6}}][Cr{{({{C}_{2}}{{O}_{4}})}_{3}}]\] (4) \[[Pt{{(en)}_{3}}]{{(S{{O}_{4}})}_{2}}\]A) 1, 2 and 3 are correct.
B) 1 and 2 are correct.
C) 2 and 4 are correct.
D) 1 and 3 are correct.
Correct Answer: D
Solution :
The compounds in which cation and anion both are complex and metals have same coordination number, exhibit coordination isomerism. It involves the exchange of ligands between cation and anion. (i)\[\left. \begin{align} & [Cu{{(N{{H}_{3}})}_{4}}][PtC{{l}_{4}},] \\ & [CuC{{l}_{4}}][Pt{{(N{{h}_{3}})}_{4}}] \\ \end{align} \right\}(coordination\,isomers)\] \[C.N.=4\] (ii) \[\left. \begin{align} & [Co{{(N{{H}_{3}})}_{6}}][Cr{{({{C}_{2}}{{O}_{4}})}_{3}}], \\ & [Co{{({{C}_{2}}{{O}_{4}})}_{3}}][Cr{{(N{{H}_{3}})}_{6}}] \\ \end{align} \right\}(coordination\,isomers)\] \[C.\text{ }N=6[\because {{C}_{2}}{{O}_{4}}is\text{ }bidentate\text{ }ligand]\]
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