A) \[9.61\times {{10}^{14}}\]
B) \[4.12\times {{10}^{13}}\]
C) \[1.51\times {{10}^{12}}\]
D) \[2.13\times {{10}^{11}}\]
Correct Answer: C
Solution :
Energy of each photon, \[E=\frac{hc}{\lambda }=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{300\times {{10}^{-9}}}\] \[E=6.6\times {{10}^{-19}}J\] Power of source \[P=IA=1.0\times 1.0\times {{10}^{-4}}={{10}^{-4}}W\] So, number of photons per sec as \[\frac{N}{t}=\frac{P}{E}=\frac{{{10}^{-4}}}{6.6\times {{10}^{-19}}}\] \[\Rightarrow \] \[N'=1.51\times {{10}^{12}}/s\] Number of electrons emitted is \[N'=\frac{1}{100}\times \frac{{{10}^{-4}}}{6.6\times {{10}^{-19}}}\] \[\Rightarrow \] \[N'=1.51\times {{10}^{12}}/s\]You need to login to perform this action.
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