BHU PMT BHU PMT (Mains) Solved Paper-2009

  • question_answer
    If the intermolecular forces vanish away, the volume occupied by the molecules contained in 4.5 kg water of NTP will be given by

    A)  \[5.6\,{{m}^{3}}\]                          

    B) \[4.5\,{{m}^{3}}\]

    C)  \[11.2\,{{m}^{3}}\]                        

    D)  5.6L

    Correct Answer: A

    Solution :

                     Due to vanishing of intermolecular forces, the liquid would get converted into vapour. We know that  \[18\times {{10}^{-3}}kg\]of water vapour occupies a volume of\[22.4\times {{10}^{-3}}{{m}^{3}}\]at NTP.                 So, volume occupied by 4.5 kg is                 \[\frac{22.4\times {{10}^{-3}}}{18\times {{10}^{-3}}}\times 4.5\,{{m}^{3}}=5.6\,{{m}^{3}}\]


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