Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
A gas undergoes the change in its state from position A to position B via three different paths as shown in figure. Select the correct alternative (s).
(1) temperature of the gas first increases and then decreases continuously in path 1 (2) heat absorbed/released by the gas is maximum in path 1 (3) change in internal energy in all the three paths is equal (4) in all the three paths heat is absorbed by the gas
A) 1, 2 and 3 are correct
B) 1 and 2 are correct
C) 2 and 4 are correct
D) 1 and 3 are correct
Correct Answer: A
Solution :
Internal energy (U) depends only on the initial and final states. Hence,\[\Delta U\]will be same in all the three paths. In all the three paths work done by the gas is positive (volume is increasing) and the product\[pV\]or temperature T is increasing. Therefore, internal energy is also increasing so, from first law of thermodynamics heat will be absorbed by the gas. Further area under p-V graph is maximum in path 1 while\[\Delta U\]is same for all three paths. Therefore, heat absorbed by the gas is maximum in path 1. For temperature of the gas we can see the product \[pV\]which first increases in paht 1 and then decreases us.
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