A) increase in entropy
B) decrease in entropy
C) decrease in enthalpy
D) no change in entropy
Correct Answer: A
Solution :
Since, cooling is produced, the reaction is endothermic, ie,\[\Delta H=+ve\]. \[\Delta G=\Delta H-T\Delta S,\][For spontaneous process\[\Delta G=-\text{ }ve\]] As the value of AH is positive, the value of\[\Delta S\] must be positive to get a negative value of\[\Delta G\]. Thus, the process is accompanied by increase in entropy.You need to login to perform this action.
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