A) \[0.2mH,\frac{1}{32}\mu F\]
B) \[0.4mH,\frac{1}{16}\mu F\]
C) \[0.2mH,\frac{1}{16}\mu F\]
D) \[0.4\,mH,\frac{1}{32}\mu F\]
Correct Answer: A
Solution :
At resonance, voltage across resistance is 60 V \[\Rightarrow \] \[60={{I}_{0}}R\] \[\Rightarrow \] \[{{I}_{0}}=\frac{60}{120}=0.5A\] Also, voltage across inductance is 40 V \[\Rightarrow \]\[40={{I}_{0}}{{X}_{L}}\] \[\Rightarrow \]\[80=L(4\times {{10}^{5}})\] \[\Rightarrow \] \[L=0.2mH\] Since, \[{{\omega }_{0}}=\frac{1}{\sqrt{LC}}\] \[4\times {{10}^{5}}=\frac{1}{\sqrt{0.2\times {{10}^{-3}}C}}\] \[\Rightarrow \] \[C=\frac{1}{32}\mu F\]
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