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BHU PMT BHU PMT (Mains) Solved Paper-2009

  • question_answer
    In an experiment, 0.04F was passed, through 400 mL of a 1 M solution of sodium hydroxide. What would be the pH of the solution after the electrolysis?

    A)  6                                            

    B)  13

    C)   8                                           

    D)  10

    Correct Answer: B

    Solution :

                     \[\underset{\begin{smallmatrix}  1\,mol \\  0.04\,F \end{smallmatrix}}{\mathop{NaOH}}\,\xrightarrow[{}]{{}}\underset{1\,mol}{\mathop{N{{a}^{+}}}}\,+\underset{\begin{smallmatrix}  1\,mol \\  0.04\,mol \end{smallmatrix}}{\mathop{O{{H}^{-}}}}\,\] \[\therefore \]Concentration of \[O{{H}^{-}}=\frac{0.04}{400}\times 1000={{10}^{-1}}\] \[pOH=\log [O{{H}^{-}}]=-\log {{10}^{-1}}\]                 \[=1\] \[pH=14-1=13\]


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