BHU PMT BHU PMT (Mains) Solved Paper-2009

  • question_answer
    The compound that can exhibit geometrical isomerism is

    A) \[C{{H}_{3}}{{(C{{H}_{2}})}_{4}}CHO\]

    B) \[{{(CH)}_{2}}{{(COOH)}_{2}}\]

    C)  \[{{(C{{H}_{2}})}_{2}}{{(COOH)}_{2}}\]

    D) \[{{(C{{H}_{3}})}_{2}}C=CHC{{H}_{3}}\]

    Correct Answer: B

    Solution :

                     Geometrical isomerism is exhibited by only those compounds in which at least one double bond is present and different groups are attached to the same carbon atom. \[\underset{H\text{ }\text{ }C\text{ }\text{ }COOH}{\overset{H\text{ }\text{ }C\text{ }\text{ }COOH}{\mathop{|\,\,|}}}\,\] fulfill both the conditions, so it exhibits geometrical [cis-trans) isomerism.


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