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BHU PMT BHU PMT (Mains) Solved Paper-2009

  • question_answer
    A current of 2 A passed for 5 h through a molten metal salt, deposits 22.2 g of metal having atomic weight 177. The oxidation state of metal in metal salt is

    A)  1                                            

    B)  2

    C)   3                                           

    D)  4

    Correct Answer: C

    Solution :

                     From Faraday?s first law, \[w=\frac{E}{96500}\times i\times t\] Let the oxidation state of metal is\[x\]. \[\therefore \] \[E=\frac{M}{x}\]             [where, M = atomic weight] \[\Rightarrow \]               \[22.2=\frac{177}{x\times 96500}\times 2\times 5\times 60\times 60\] \[\therefore \]  \[x=\frac{177\times 2\times 5\times 3600}{22.2\times 96500}\] Or           \[x=3\]


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