A) \[{{A}_{2}}B\]
B) \[A{{B}_{2}}\]
C) \[{{A}_{3}}{{B}_{4}}\]
D) \[{{A}_{4}}{{B}_{3}}\]
Correct Answer: C
Solution :
Atoms A occupy corners as well as face centres. Removal of face centred atoms along one axis shows that two atoms of 'A' are removed from face centres. Thus, A atoms left per unit cell\[=\frac{1}{2}\times 8+\frac{1}{2}\times 4=3\] The number of B atoms remains same. Thus, the ratio of\[A:B=3:4,\]ie,\[{{A}_{3}}{{B}_{4}}\].
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