Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
Potassium manganate\[({{K}_{2}}Mn{{O}_{4}})\]is obtained when (1) formaldehyde reacts with potassium permanganate in presence of a strong alkali (2) chlorine is passed into the solution of potassium permanganate (3)\[Mn{{O}_{2}}\]is fused with\[KOH\]in air (4)\[KMn{{O}_{4}}\]reacts with cone\[{{H}_{2}}S{{O}_{4}}\]A) 1, 2 and 3 are correct
B) 1 and 2 are correct
C) 2 and 4 are correct
D) 1 and 3 are correct
Correct Answer: D
Solution :
\[2KOH+\underset{\begin{smallmatrix} manganese \\ \,\,dioxide \end{smallmatrix}}{\mathop{Mn{{O}_{2}}}}\,+[O]\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} potassium \\ manganate \end{smallmatrix}}{\mathop{{{K}_{2}}Mn{{O}_{4}}}}\,+{{H}_{2}}O\] \[\underset{formaldehyde}{\mathop{HCHO}}\,+\underset{\begin{smallmatrix} potassium \\ permanganate \end{smallmatrix}}{\mathop{2KMn{{O}_{4}}}}\,+2\underset{alkali}{\mathop{KOH}}\,\] \[\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} potassium \\ manganate \end{smallmatrix}}{\mathop{2{{K}_{2}}Mn{{O}_{4}}}}\,+{{H}_{2}}O+HCOOH\]
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