BHU PMT BHU PMT (Mains) Solved Paper-2009

  • question_answer

    Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:

    8g of oxygen molecule has the same number of molecules as in (1) 11 g carbon dioxide (2) 11.2Lof\[S{{O}_{2}}\] (3) 5.6 L of oxygen (4) 0.1 g atom of\[He\]

    A)  1, 2 and 3 are correct

    B)  1 and 2 are correct

    C)  2 and 4 are correct

    D)  1 and 3 are correct

    Correct Answer: D

    Solution :

                     Number   of   molecules   in   8g   of \[{{O}_{2}}=\frac{8}{32}\times {{N}_{0}}=\frac{{{N}_{0}}}{4}\] (1) Number of molecules in 11 g of\[C{{O}_{2}}\] \[=\frac{11}{44}\times {{N}_{0}}=\frac{{{N}_{0}}}{4}\] (2) Number of molecules in 11.2 L of\[S{{O}_{2}}\] \[=\frac{11.2}{22.4}\times {{N}_{0}}=\frac{{{N}_{0}}}{2}\] (3) Number of molecules in\[5.6\text{ }L\text{ }{{\text{O}}_{2}}\]                 \[=\frac{5.6}{22.4}\times {{N}_{0}}\]                 \[=\frac{{{N}_{0}}}{4}\] (4) Number of molecules in 0.1 g atom of He \[=0.1\times {{N}_{0}}\] \[\therefore \]8g of\[{{O}_{2}}\]has the same number of molecules as in 11 g of\[C{{O}_{2}}\]and 5.6 L of\[{{O}_{2}}\].                


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