Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
For the following conversion,\[C{{H}_{ 3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl\xrightarrow{{}}{{C}_{2}}{{H}_{5}}-{{C}_{2}}{{H}_{5}}\]the Reagent used, are (1) Mg, dry ether/\[{{H}_{2}}O\] (2)\[LiAl{{H}_{4}}\] (3) \[Zn/HCl\] (4) \[{{B}_{2}}{{H}_{6}}/THF\]A) 1, 2 and 3 are correct
B) 1 and 2 are correct
C) 2 and 4 are correct
D) 1 and 3 are correct
Correct Answer: A
Solution :
(1) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl\xrightarrow[dry\,ether]{Mg}\] \[C{{H}_{3}}{{(C{{H}_{2}})}_{3}}MgCl\xrightarrow[{}]{{{H}_{2}}O}\underset{n-bu\tan e}{\mathop{C{{H}_{3}}{{(C{{H}_{2}})}_{2}}C{{H}_{3}}}}\,\] (2) \[C{{H}_{3}}{{(C{{H}_{2}})}_{3}}Cl\xrightarrow[{}]{LiAl{{H}_{4}}}\underset{n-bu\tan e}{\mathop{C{{H}_{3}}{{(C{{H}_{2}})}_{2}}C{{H}_{3}}}}\,\] (3) \[C{{H}_{3}}{{(C{{H}_{2}})}_{3}}Cl\xrightarrow[{}]{Zn/HCl}\underset{n-bu\tan e}{\mathop{{{C}_{2}}{{H}_{5}}-{{C}_{2}}{{H}_{5}}}}\,\] (4)\[{{B}_{2}}{{H}_{6}}/THF\]does not convert\[Cl\]group into\[H\].
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