Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
Zwitter ion is formed in case of (1) glycine (2) sulphanilic acid (3) salicylic acid picric acidA) 1, 2 and 3 are correct
B) 1 and 2 are correct
C) 2 and 4 are correct
D) 1 and 3 are correct
Correct Answer: B
Solution :
Glycine\[(C{{H}_{2}}N{{H}_{2}}COOH)\]and sulphanilic acid \[({{H}_{2}}N{{C}_{6}}{{H}_{4}}S{{O}_{3}}H)\]both have acid (\[COOH\] or\[S{{O}_{3}}H\]) as well as basic (\[N{{H}_{2}}\]) group. So, they exist as Zwitter ion.
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