A) \[\frac{R}{4}\]
B) \[\frac{R}{2}\]
C) \[2R\]
D) \[4R\]
Correct Answer: B
Solution :
The total energy of a satellite at a height h \[=-\frac{GMm}{2(R+h)}\] Potential energy at a height 2R from surface of earth \[=-\frac{GMm}{(2R+R)}=-\frac{GMm}{3R}\] According to the question, \[-\frac{GMm}{2(R+h)}=-\frac{GMm}{3R}\] \[h=\frac{R}{2}\]You need to login to perform this action.
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